Comments on: Nested Variable Substitution and Predefined BASH Variables in Linux – Part 11

By: dragonmouth

dragonmouth — Thu, 30 Aug 2018 21:45:23 +0000

“What in case of multiple variable substitution, where we are dealing with lots of variable and 100’s of lines of code???”

Unfortunately you did not provide an example of multiple variables. How are we newbies to learn if we are shown only the most basic usage?

Doesn’t the '-x' switch mean EXPORTABLE, not Executable as explained in Part 10 of these series?

By: buge

buge — Sat, 03 Jan 2015 20:03:59 +0000

echo ${!y}

By: Avishek Kumar

Avishek Kumar — Mon, 23 Jun 2014 07:58:46 +0000

In reply to Igor.

Thanks for your feedback.

But Let me know – What in case of multiple variable substitution, where we are dealing with lots of variable and 100’s of lines of code???
‘eval’ command comes to rescue there.

By: Igor

Igor — Thu, 19 Jun 2014 15:51:31 +0000

You don’t need to use eval to assign value of x to y.
You will get the same output using
y=$x